Is this correct? The quotient of f(x)= x-3 and g(x) = x-5 is 3/5 and the domain is [5, infinity)?
The quotient should just be (x-3)/(x-5), since if we sub in x =1, we get (1-3)/(1-5) which equals -2/-4 and that is 1/2. So it wouldn't be 3/5. As for the domain for either of the functions, x should be all real values.
it will be 2.. for domain\[-\infty \to +\infty\] if f(x) is divided by g(x)
x can't equal 5
x can equal 5, it would just mean that f(5) = 0.
If x = 5 you would have 2/0 which is not possible
because zero can't be in the denominator
Wait, aren't they two separate functions?
Oh my mistake, she was looking for the function of the quotient, not f(x) or g(x). Yeah, x cannot be 5
so for interval notation is it \[[-5,\infty)\]
That's only part of the solution
actually...
i mean \[[5,\infty)\]
(-infinity, 5), (5, +infinity)
That's the solution
the quotient is equal to 1 the remainder is equal to 2 (x - 3)/(x - 5) = 1 + 2/(x-5)
so is it a union for the domain?
yes
sorry, i didn't mean to post that so many times.
and this is all in parenthesis?
yes, correct because 5 is not included in the solution.
how do you know that the domain is a union and not one single set of intervals?
Because the solution is incomplete without the other set. Providing only one set is incomplete.
When you are providing a solution, you have to provide the complete solution.
ok, i think i got it. it's basically saying that the domain is negative infinty, not including 5, and 5 to infinity
Precisely
thank you :)
R\{5} is probably the most succinct way to write the domain using set notation
okay, my teacher hasn't taught that yet, i'm not sure if she will, so i'll just use a union.
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