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Mathematics 19 Online
OpenStudy (anonymous):

kindly help me, just want to check my ans. FIND THE SUM: x^2y-xy xy^2-3xy 2x^2y-xy^2+5xy

OpenStudy (anonymous):

you mean factor

OpenStudy (anonymous):

you mean \[x^2y-xy+xy^2-3xy+2x^2y-xy^2+5xy\]?

OpenStudy (anonymous):

if so combine like terms as they say in the math biz

OpenStudy (anonymous):

^ u prob right

OpenStudy (anonymous):

it is x^2y-4xy+xy^2

OpenStudy (anonymous):

ur adding the firsst two equations and the third equation is the answer then its wrong

OpenStudy (anonymous):

\[3x^2y+xy\] i think

OpenStudy (anonymous):

\[x ^{2}y -xy+xy ^{2}-3xy =x ^{2}y-4xy+\]

OpenStudy (anonymous):

xy^2

OpenStudy (anonymous):

anyone can show me the solution? because we have different answers.. i want to see where i get wrong

OpenStudy (anonymous):

tell me what u hav to add if u hav to add the first two equations or all the three????

OpenStudy (anonymous):

\[x^2y-xy+xy^2-3xy+2x^2y-xy^2+5xy\] \[(x^2y+2x^2y)+(xy^2-xy^2)+(5xy-3xy-xy)\]

OpenStudy (anonymous):

the parentheses are unnecessary i just put them there to show that i grouped "like terms" together. like terms means same variables with same exponents

OpenStudy (anonymous):

all the 3

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

?

OpenStudy (anonymous):

there are three like terms yes

OpenStudy (anonymous):

the first gives \[3x^2y\] the second is 0, and the third is \[xy\]

OpenStudy (anonymous):

satellite73 how can u type the equations with exponents?

OpenStudy (anonymous):

i am using latex

OpenStudy (anonymous):

what is that?

OpenStudy (anonymous):

i can't show you here because it just comes up as symbols. i can show you in chat if you like

OpenStudy (anonymous):

see here there is a equation box there u can write equations

OpenStudy (anonymous):

ok get it

OpenStudy (anonymous):

thank you:)

OpenStudy (anonymous):

welcome)

OpenStudy (anonymous):

how about this one: \[4x-{3+[4-(x^2-3x)+x^3]-[3x^2+(-3+4x)]+7x}\]

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