FIND AN EQUATION OF THE TANGENT LINE TO THE GRAPH OF f AT THE GIVEN POINT.
(X+1)/(X-1), {1/2,-3}

Question

FIND AN EQUATION OF THE TANGENT LINE TO THE GRAPH OF f AT THE GIVEN POINT.
(X+1)/(X-1),  {1/2,-3}

anonymous · Answer

take the derivative, plug in 1/2

anonymous · Answer

AND F(X)=(1+SINX)/(1-SINX),    {(PIE,1}

anonymous · Answer

derivative of 
$$\frac{x+1}{x-1}$$ is
$$-\frac{2}{(x-1)^2}$$ replace x by 1/2 to get your slope

anonymous · Answer

second problem same as first.  derivative is 
$$\frac{2\cos(x)}{(1-\sin(x))^2}$$

anonymous · Answer

FOR FIRST DERIVATIVE WHY DID I GET -X/{2(X-1)^2???

anonymous · Answer

ONCE I FIND THE SLOPE THEN WHAT??

anonymous · Answer

Satellite's derivative is correct. To avoid mistakes in future, you should not simplify the derivative: there is no need to break it down since you are just inputting values for x; that only increases chances to make a mistake, and in exam waste time.

anonymous · Answer

Once you find slope, equation is
y=[f'(1/2)][x-(1/2)] - 3