Question

Lecture #12 homework check. Same drill. I want to swap answers for the questions that are not at the end of the book to see if I messed up.

Answer 1

A&E 11-20) I'm not very confident (especially since I'm about to go to sleep), but using the estimated atomic radius without checking, this is what I got:\[Kr<Ne<H_2<O_2<N_2<Cl_2\]
A&E 11-26)
a) Phosphine (PH3), no hydrogen bonding
b) ethylene glycol, bigger molecules have greater polarizability (LDF)
c) 2-2-dimethylpropanol, bigger molecules have greater polarizability (LDF)

A&E 11-30)
a) Iodine is too big for effective hydrogen bonding.
b) HF; F is more electronegative than O, so HF should be more polar than water.
c) HF if the above reasoning is correct.