Question

how do we take the partial derivatives of 3 variables.Meaning in terms of fu, fv, fw?
f(u,v,w) =(w^u)(v^3)(e^(9w-(3v^2)))+5uv

Answer 1

take all other variables as constants and do normal differentiation

Answer 2

u get it?

Answer 3

umm.. lemme check

Answer 4

for df/du treat v and w as normal constants and differentiate

Answer 5

fu= (w^u)*ln(w)*v^3*e^(9w-3v^2) +5v
fv= (w^u)*3v^2(e^9w-3v^2) + (w^u)(v^3)(e^(9w-(3v^2) * ( 9w-6v) +5u

so in fv, at the end do we take ( 9w-6v) +5u or just (-6v)+5u

man it took long to type :(