Find the 8th term of the arithmetic sequence: 3, 8, 13, 18, ... Find the 11th term of the arithmetic sequence: -3, -5, -7, -9, ...
difference is 5 3 + 7*5 = 38
11th term difference is -2 -3 +10(-2) = -23
d = -2 an = a1 + (n-1)(d) a(11) = -3 + (10)(-2) = -23; yep
Find the indicated sum for the arithmetic series: \[\sum_{k-1}^{15} (50-20k)\]
last one please
the sum from 1 to 15 eh ....... i can do it the long way but I think the short cut is: (a1 + a15)(15) ------------- 2 ill have to dbl chk meself :)
the main answer is 2?
just hold on :)
ok thanks
im thinking if I did it right its gonna be -110; but let me check on that first
ok
i guess that wasnt the formula I was thinking it was :) When I add all the values up I get -1650
ok ya thats right thanks :)
i had the right formula i just forgot to multiply in the 15 :) same answer
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