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OpenStudy (gg):

what is matrix of linear transformation? how to write it?

OpenStudy (anonymous):

this is one of the best site for info: http://tutorial.math.lamar.edu/Classes/LinAlg/LinearTransformations.aspx

OpenStudy (gg):

can I write linear transformation here and you write me matrix? :)

OpenStudy (anonymous):

this one too: http://en.wikipedia.org/wiki/Transformation_matrix If one has a linear transformation T(x) in functional form, it is easy to determine the transformation matrix A by simply transforming each of the vectors of the standard basis by T and then inserting the results into the columns of a matrix. In other words, A= [ T(e1) T(e2).... T(e n) ] it's hard to write matrices here - please see links

OpenStudy (gg):

it won't be hard, it's 3x3 matrix, just write which matrix did u get. I did something, but I'm not sure if it's correct. I got matrix [ 1, -6, 5; 2, 9 -5; 0, 0, 0]. Is this good?

OpenStudy (anonymous):

sorry... just got back here we go:

OpenStudy (anonymous):

Example: The columns of \[I1=\left[\begin{matrix}1 & 0 \\ 0 & 1\end{matrix}\right]\] are \[e1=\left(\begin{matrix}1 \\ 0\end{matrix}\right) and e2=\left(\begin{matrix}0 \\ 1\end{matrix}\right)\] Suppose T is a linear transformation from R2 to R3 such that

OpenStudy (anonymous):

\[T(e1)=\left(\begin{matrix}5 \\ -7\\ 2\end{matrix}\right)\] and \[T(e2)=\left(\begin{matrix}-3 \\ 8\\ 0\end{matrix}\right)\] To find a formula for the image of an arbitrary x in R2 write: \[x=\left(\begin{matrix}x1 \\ x2\end{matrix}\right)=x1\left(\begin{matrix}1 \\ 0\end{matrix}\right)+x2\left(\begin{matrix}0 \\ 1\end{matrix}\right)\]

OpenStudy (anonymous):

=x1e1 +x2e2 Since T is a linear transformation, T(x)=x1*T(e1) +x2*T(e2)= ......= \[\left(\begin{matrix}5x1-3x2 \\ 7x1+8x2\\ 2x1+0\end{matrix}\right)\] You can re-write it as: T(x)=[T(e1) T(e2) [x1/x2] = Ax

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