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Mathematics 20 Online
OpenStudy (anonymous):

The integral of xarccos(x)dx It's supposed to be solved using a table of integrals...however, my prof. wants us to solve all our HW probs NOT using a table of integrals. Any help is appreciated, even any hints about how to go about solving w/o integral table would be great! Thanks

OpenStudy (anonymous):

by parts

OpenStudy (anonymous):

u = cos^-1(x) dv = x dx

OpenStudy (anonymous):

du = -1/ sqrt(1-x^2) dx v = (1/2)x^2

OpenStudy (anonymous):

Thanks! I was leaning towards parts, but was second guessing.

OpenStudy (anonymous):

it should be easy

OpenStudy (anonymous):

v du is just an algebraic function

OpenStudy (anonymous):

easy to integrate

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

Cool. I'll give it a shot

OpenStudy (anonymous):

u need trig sub

OpenStudy (anonymous):

instead of parts altogether? Or in addition to?

OpenStudy (anonymous):

no u need parts

OpenStudy (anonymous):

then integration by parts says its uv - integral v du

OpenStudy (anonymous):

v du is something like x^2 / sqrt(1-x^2) with some constant floating around

OpenStudy (anonymous):

Oh i see where it's going to need trig substitution

OpenStudy (anonymous):

that integral needs a trig substitution

OpenStudy (anonymous):

cool cool, yea that makes sense

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