The integral of xarccos(x)dx It's supposed to be solved using a table of integrals...however, my prof. wants us to solve all our HW probs NOT using a table of integrals. Any help is appreciated, even any hints about how to go about solving w/o integral table would be great! Thanks
by parts
u = cos^-1(x) dv = x dx
du = -1/ sqrt(1-x^2) dx v = (1/2)x^2
Thanks! I was leaning towards parts, but was second guessing.
it should be easy
v du is just an algebraic function
easy to integrate
wait
Cool. I'll give it a shot
u need trig sub
instead of parts altogether? Or in addition to?
no u need parts
then integration by parts says its uv - integral v du
v du is something like x^2 / sqrt(1-x^2) with some constant floating around
Oh i see where it's going to need trig substitution
that integral needs a trig substitution
cool cool, yea that makes sense
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