Question

need help on this question, ill post down

Answer 1

\[\int\limits_{}dx/(x+4)^{3}\]

Answer 2

in that one, i took u = (X + 4) and du=dx so that it been that : \[ \int\limits_{}(1/u^{3}) * du\]

Answer 3

then its : \[1/(x+4)^{2} + C\]

Answer 4

true?

Answer 5

no

Answer 6

u are missing a factor of (-1/2)

Answer 7

No, not exactly. Someone else can correct me if I'm wrong, but remember that \[\int\limits x^r dx => r+1 = c => x^c/c\] Sorry, crude expression of the rule, but...

Now also notice that in \[\int\limits (1/u^3) du\] 1/u^3 can be written as u^-3. Try integrating that term instead, and you should get \[(u^-2)/-2 + C = 1/-2u^2 + C = 1/-2(x+4)^2 +C\]

Anyone have a better answer, or is this correct?

Answer 8

Make sense, Korcan?

Answer 9

this correct tangent

Answer 10

Eh?

Answer 11

i said i agree with ur answer - it is correct

Answer 12

Ah OK. Thanks for clarifying.

Answer 13

it is usually written -1 /2(x+4)^2 but ur answer is perfectly correct

Answer 14

thanks :D

Answer 15

No problem, and again thanks for seconding that, Jimmy.