Question

integrate x^2/1+x^2 dx

Answer 1

\[\int\limits (1+x^2-1)/(1+x^2)\]

Answer 2

why did u do that?

Answer 3

\[\int\limits 1+(1/1+x^2) dx\]

Answer 4

addind n subtracting 1 in numerator, then splitting up the denominator

Answer 5

i didnt know
u doing like magic

Answer 6

\[x+ \tan ^{-1} x +c\]

Answer 7

its there logic process?

Answer 8

no

Answer 9

:(

Answer 10

\[\int\limits{{ x^2} \over {1+x^2}} dx\]

Answer 11

yes just divide. you long division and you will get the same thing.

Answer 12

is this one u want to evaluate?

Answer 13

yes

Answer 14

we can have a similar expression in the numerator by just adding n subtracting 1

Answer 15

ok... but i finish that chapter already and i didnt see my professor doing that...

Answer 16

\[\int\limits {{ 1+x^2-1} \over {1+x^2}} dx\]

Answer 17

but why u add and subtract 1.

Answer 18

now split up the denominator

Answer 19

give reason

Answer 20

reason 4 what?

Answer 21

why u adding 1

Answer 22

because u have 1+x^2 in the denominator

Answer 23

ok

Answer 24

ok u can keep telling me

Answer 25

so what u do next

Answer 26

you really can just divide. really. just divide
\[x^2+1\] into \[x^2\] and you will get the same thing. that is if they trick annoys you

Answer 27

yes satellite is right, go for the long division

Answer 28

so what should i get?

Answer 29

1- 1/(1+x^2)

Answer 30

u got it?