Question

The perimeter of an isosceles right angled
triangle is 2p cm. Find out the area of the same
triangle.
(A) (2 + root 2 )p^2 cm2 (B) (2 - root– 2 )p^2 cm2
(C) (3- 2 root 2 )p^2 cm2 (D) (3 + 2 root 2 )p^2 cm2

Answer 1

iso rt tri; isnt that a 45-45-90?

Answer 2

yes

Answer 3

Yes

Answer 4

1,1,sqrt(2)

Answer 5

x(1+1+sqrt(2)) = 2pi maybe?

Answer 6

mistook p tor pi lol

Answer 7

so s + s + sroot2 = 2p
find s
A = 0.5 s^2

Answer 8

Are we to substitute s=2p/(2+ root2)?

Answer 9

was trying to find the scalar used to make the perimeter equal 2pi to adjust the legs :) good idea, wrong problem tho lol

Answer 10

So, I am getting (2p^2)/6+4 root 2 as the final answer(after simplication). But exactly which option is that expression matching? If any mistake is there, please find out.

Answer 11

s(2 + sqrt(2)) = 2p

s = 2p/(2+sqrt(2))

[2p/(2+sqrt(2))]^2 4p^2
-------------- = --------------
2/1 2(4+2+4sqrt(2))


2p^2 p^2
-------------- = ----------- ; if I did it right
6+4sqrt(2) 3+2sqrt(2)

Answer 12

So, which option is correct?

Answer 13

dunno yet, gotta see where i made a mistake first lol

Answer 14

I think u have solved correctly. I think the step may be to rationalise the expression.

Answer 15

good thinking

Answer 16

p^2 3-2sqrt(2) p^2 (3-2sqrt(2))
----------- * ---------- = --------------
3+2sqrt(2) 3-2sqrt(2) 9-4(2)

Answer 17

C is my best bet

Answer 18

Eureka!!!! you're right. It can be rewritten as (3-2 root 2)(p^2).So, obviously option(c) is correct. Thanks a lot..

Answer 19

youre welcome :)

Answer 20

Thanks. If any doubt, I will come tomorrow mostly at the same time with several maths questions. I hope u answer them. Thanks a lot!!! Gudbye!!!