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Mathematics 24 Online
OpenStudy (anonymous):

Find all solutions of the equation. x^4 + 3x^3 - 12x^2 - 6x + 20 = 0

OpenStudy (anonymous):

do you know polynomial division?

OpenStudy (anonymous):

if not I wont be able to teach u over the net, its too hard explaining it over the net.

OpenStudy (anonymous):

Like synthetic? yeah.

OpenStudy (anonymous):

yeh, so you guess factors of the constant term and sub into the expression until you get a zero

OpenStudy (anonymous):

try +-2, +-4 , +- 5

OpenStudy (anonymous):

oh mmkay I can do that XD

OpenStudy (anonymous):

i think it will be either 2 or 4 ,

OpenStudy (anonymous):

should get 2

OpenStudy (anonymous):

2 is,but I need four answers...

OpenStudy (anonymous):

then you can say (x-2) is a factor and divide into the quartic

OpenStudy (anonymous):

ahhh

OpenStudy (anonymous):

but you probably dont want that, because that will reduce it to a cubic , and you will have to divide again

OpenStudy (anonymous):

if you try other factors of 20 into the expression you will see that (x+5) is also a factor

OpenStudy (anonymous):

then you can divide (x-2)(x-5) into the quartic, that will leave you with a quadratic, which can be factored easily.

OpenStudy (anonymous):

mmkay

OpenStudy (anonymous):

is it (x-5) or (x+5)?

OpenStudy (anonymous):

x^2-2

OpenStudy (anonymous):

And now what?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

yeh it should be x+5

OpenStudy (anonymous):

then its factored, set each factor to zero find the solns

OpenStudy (anonymous):

ohhhh so + or - sqrt2

OpenStudy (anonymous):

yes, and then other two from the linear factors

OpenStudy (anonymous):

:D Thanks!

OpenStudy (anonymous):

whenever you have to solve a quadratic or higher order, first step is factor it , usually by polynomial division

OpenStudy (anonymous):

I'll remember that.

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