Mathematics
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OpenStudy (anonymous):
Find all solutions of the equation.
x^4 + 3x^3 - 12x^2 - 6x + 20 = 0
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OpenStudy (anonymous):
do you know polynomial division?
OpenStudy (anonymous):
if not I wont be able to teach u over the net, its too hard explaining it over the net.
OpenStudy (anonymous):
Like synthetic? yeah.
OpenStudy (anonymous):
yeh, so you guess factors of the constant term and sub into the expression until you get a zero
OpenStudy (anonymous):
try +-2, +-4 , +- 5
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OpenStudy (anonymous):
oh mmkay I can do that XD
OpenStudy (anonymous):
i think it will be either 2 or 4 ,
OpenStudy (anonymous):
should get 2
OpenStudy (anonymous):
2 is,but I need four answers...
OpenStudy (anonymous):
then you can say (x-2) is a factor and divide into the quartic
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OpenStudy (anonymous):
ahhh
OpenStudy (anonymous):
but you probably dont want that, because that will reduce it to a cubic , and you will have to divide again
OpenStudy (anonymous):
if you try other factors of 20 into the expression you will see that
(x+5) is also a factor
OpenStudy (anonymous):
then you can divide (x-2)(x-5) into the quartic, that will leave you with a quadratic, which can be factored easily.
OpenStudy (anonymous):
mmkay
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OpenStudy (anonymous):
is it (x-5) or (x+5)?
OpenStudy (anonymous):
x^2-2
OpenStudy (anonymous):
And now what?
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yeh it should be x+5
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OpenStudy (anonymous):
then its factored, set each factor to zero find the solns
OpenStudy (anonymous):
ohhhh so + or - sqrt2
OpenStudy (anonymous):
yes, and then other two from the linear factors
OpenStudy (anonymous):
:D Thanks!
OpenStudy (anonymous):
whenever you have to solve a quadratic or higher order, first step is factor it , usually by polynomial division
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OpenStudy (anonymous):
I'll remember that.