Find the magnitude and direction of vector XY for X(1, -4) and Y(6, 3). Show all work.
magnitude is root(74)
direction arctan (1.4)
how do you get that? I dont understand.
the magnitude is the distance between the 2 pts
\[=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
whts the vector XY?
@him1618 I dont know. Thats all I was given. @angela210793 isnt that the distance formula? if so I understand!
XY=(6-1)=(5) (4+4) (8)
vector XY can be obtained by X - Y..understand?
@angela its 5,7
yea tht's the distance and @Him aren't wht i wrote the coordinates of XY?
wht's 5.7?
XY is a vector angela it doesnt have coordinates im saying the vector XY is 5,7..u wrote 5,8
yea ur right is 5;7(typing mistake) and as far as i know a vector does have coordinates...how come it hasn't?
ur confusing it...u mean to say 5 and 7 are the coordinates of a vector..they are called COMPONENTS of a vector
ONLY in the case of a POSITION VECTOR, the components of a vector become the coordinates of a point..understand?
\[\tan x=7/5\] \[x = \tan^{-1} (7/5)\] \[\tan x=8/5\] \[x = \tan^{-1} (8/5)\] is this the right format?
Hmmm...:(:(:( we call them coordinates as well :(:( Sorry my fault :( :)
im looking at finding the direction, btw
the first ones right @angela: no prob, my fault
Thank You.
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