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Mathematics 17 Online
OpenStudy (anonymous):

nC4=70 calculate n?

OpenStudy (anonymous):

n = 8

OpenStudy (anonymous):

explain plzzzzzz

OpenStudy (anonymous):

\[\dbinom{8}{4}=\frac{8\times 7\times 6\times 5}{4\times 3\times 2}=2\times 7\times 5 = 70\]

OpenStudy (anonymous):

i guess if you want a method i did not really use one. i know \[\frac{10}{4}\] is large (210) so i just tried 8 and it worked

OpenStudy (anonymous):

any generic method. this u did as u kno answer is 8.......... ohhh got hw the way u think..

OpenStudy (anonymous):

yea i just guessed and got it on the first try. if you write \[\frac{n!}{4!\times (n-4)!}=70\] i think this would be a pain to solve using algebra.

OpenStudy (anonymous):

I did but was not able to solve equation dear..

OpenStudy (anonymous):

ya anyway fine

OpenStudy (amistre64):

nC4 = nP4/4! = 70 nP4 = 70(4!) n*(n-1)*(n-2)*(n-3) = 1680 (n^2 -n)(n^2 -5n+6) = 1680 n^2 -5n +6 n^2 -n -------------- n^4 -5n^3 +6n^2 -n^3 +5n^2 -6n --------------------- n^4 -6n^3 +11n^2 -6n = 1680 n^4 -6n^3 +11n^2 -6n -1680= 0 We can hash out the details, but when you graph it this has roots at -5 and 8; since -5 is prolly outside our scope of interest; n=8

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