Whats the margin of error?
ask a statistician
\[E = \frac{(z_{a/2})^2(.25)}{\sqrt{n}}\text{ i think}\]
.25 can be revamped to be (x/n)*(1-(1/n)) maybe
You know the answer to your own question....
..... wrong formula. This is why a loathe memorization of formulas .... if you cant remember them your outta luck
I agree
\[e=z_{a/2}\sqrt{\frac{p.q}{n}}\]
Does anybody here even know statistics at this level?
:) this is elementary statistics class; they give you the formulas cause the math behind them is so convoluted
Oh, well, that's a relief...
i just aint good at memorizing things at my age :) i forget more than i retain
\[\epsilon = .25 * 1.96/\sqrt{n} = .25 * 1,96./\sqrt{550} = 0.021\]
OOpps,,sorry... actually\[\epsilon = z{(_{\gamma})} / \sqrt{4n} = 1.96/\sqrt{4*550} =0.0418\]
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