Question

the integral of cosx(1+sin^2x)dx
I was trying to solve using parts...but I am not getting to the correct answer. Any help appreciated!

Answer 1

try u-substitution.
distribute cosx, then break the integral up
\[\int \cos(x)dx + \int \sin^2(x)\cos(x)dx\]
fist integral is basic. In the second, let u = sinx

Answer 2

Oh yea, that worked perfectly! Thanks for the suggestion

Answer 3

Oh, sorry... that was suppose to be
let u = sin(x) so du = cos(x)dx, and
\[\int (1+u^2)du\]
But glad you got it!

Answer 4

Yep, got it. Thanks!