Question

add. simplify if possible
x + 1
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x^2-2x+ x^2-5x+4

Answer 1

If I assume there is a 1 missing from the end of your first denominator, then

\[\dfrac{x}{(x-1)^2} +\dfrac{1}{(x-4)(x-1)}=\dfrac{1}{(x-1)} \bigg( x+ \dfrac{1}{(x-4)} \bigg)\]

\[=\dfrac{1}{(x-1)} \bigg( \dfrac{x^2-4x+1}{(x-4)} \bigg)= \dfrac{x^2-4x+1}{(x-1)(x-4)}\]

which cannot be simplified further.

(Heh, I have just realized the LaTeX works, sortah)