Mathematics
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OpenStudy (anonymous):
Given: f(x)=x^2+3x+1 Determine the value of
f(b+h)-f(b)/h
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OpenStudy (anonymous):
first derivative test? everywhere you see x substitute for b+h
OpenStudy (anonymous):
(b+h)^2+3(b+h)+1-(b^2+3b+1)/h
OpenStudy (anonymous):
2x+3
OpenStudy (anonymous):
\[\frac{b^2+2bh+h^2-b^2-3b-1}{h}\]
OpenStudy (anonymous):
i ended up with 2b+h
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OpenStudy (anonymous):
sorry i missed out a peace
OpenStudy (anonymous):
yes your correct...good job!
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
i believe you may be missing a 3 though maybe its a mistake i made...
OpenStudy (anonymous):
you're welcome! btw...
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OpenStudy (anonymous):
i got 2b+h+3 is this the lim as h->0?
OpenStudy (anonymous):
I am still a little unsure of how I solved it because I don't completely understand where you substitute the x^2+3x-1
OpenStudy (anonymous):
do you mean for the f(b+h)?
OpenStudy (anonymous):
in the frist function everywhere you see x you put (b+h) so it'll be (b+h)^2+3(b+h)-1
OpenStudy (anonymous):
your right!!!!
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OpenStudy (anonymous):
thank you for pointing out the missing 3
OpenStudy (anonymous):
\[\frac{b^2+2bh+h^2+3b+3h+1-b^2-3b-1}{h}\]
OpenStudy (anonymous):
lol yes because when you expane it...lol i thought it was wrong
you're welcome everyone makes mistakes
anything else you dont understand??
OpenStudy (anonymous):
well i am having a problem figuring out the coordinates to a graph i have to draw.
OpenStudy (anonymous):
post it in another question
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OpenStudy (anonymous):
i posted it