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Mathematics 16 Online
OpenStudy (anonymous):

Given: f(x)=x^2+3x+1 Determine the value of f(b+h)-f(b)/h

OpenStudy (anonymous):

first derivative test? everywhere you see x substitute for b+h

OpenStudy (anonymous):

(b+h)^2+3(b+h)+1-(b^2+3b+1)/h

OpenStudy (anonymous):

2x+3

OpenStudy (anonymous):

\[\frac{b^2+2bh+h^2-b^2-3b-1}{h}\]

OpenStudy (anonymous):

i ended up with 2b+h

OpenStudy (anonymous):

sorry i missed out a peace

OpenStudy (anonymous):

yes your correct...good job!

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

i believe you may be missing a 3 though maybe its a mistake i made...

OpenStudy (anonymous):

you're welcome! btw...

OpenStudy (anonymous):

i got 2b+h+3 is this the lim as h->0?

OpenStudy (anonymous):

I am still a little unsure of how I solved it because I don't completely understand where you substitute the x^2+3x-1

OpenStudy (anonymous):

do you mean for the f(b+h)?

OpenStudy (anonymous):

in the frist function everywhere you see x you put (b+h) so it'll be (b+h)^2+3(b+h)-1

OpenStudy (anonymous):

your right!!!!

OpenStudy (anonymous):

thank you for pointing out the missing 3

OpenStudy (anonymous):

\[\frac{b^2+2bh+h^2+3b+3h+1-b^2-3b-1}{h}\]

OpenStudy (anonymous):

lol yes because when you expane it...lol i thought it was wrong you're welcome everyone makes mistakes anything else you dont understand??

OpenStudy (anonymous):

well i am having a problem figuring out the coordinates to a graph i have to draw.

OpenStudy (anonymous):

post it in another question

OpenStudy (anonymous):

i posted it

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