Can anyone help me in finding the min/max with this online graphing calculator? http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html
What is the function you're trying to graph?
f(x) +-.000006x^4 + .0017x^3 +.03x^ -24x+110, I am having trouble finding the min/max
I can just tell you what the min and max is...lol
wait, why is there a +- at the beginning of f(x)?
which one is it?
Oops supposed to be a negative
LOL...you can tell the answer, I won't tell
I went to that online calculator and it gives A LOT of information The question is as follows, I am not good with word problems.
I can find it but it will take a while...remember you can also take the double prime of the function...
If it doesn't have a domain, then there is no min or max
The avg. cost (in dollars) per item of manufacturing x thousand cans of spray paint is given by: -.000006x^4 + .0017x^3 +.03x^ -24x+1110 How many cans should be manufactured if the average cost is to be as low as possible? What is the average coast in that case?
There was no domain given
well, we can eliminate anything less than zero, so the domain is x > 0
Double prime...you lost me there
matter of fact...the domain is x >= 1
f''(x)
Right
The minimum of the function is -988, but I don't know if it applies here because x and y both have to be positive in order for cost and no of cans to make sense
do you mind telling my how you got that
Oh and Thank You!
I used my calc, but trust me, I highly doubt that it applies here...
x and y values must be positive...cost can't be negative and no. of cans can't be negative either...
There is no max....max is infinity
Maybe that is y I am having issues with this one...so since this is a polynomial wouldn't there be more that one min....with the peaks and valleys
Yes, you're right, but, I only see two so far because of the window limit.
Oh ok....TY
Is your teacher trying to torture you on purpose?
You know what....I'm going to take f''(x) myself and find out all the possible min, maxes
f''(x) = 51x/5000 + 18/x^26
Graph that
Yes....pure toture
Don't worry ...we will figure this out...
What is that function you just gave me
that is f"(x)
ok
Okay, I have it....You have to find f'(x) and f''(x). Set f'(x) = 0 and solve for x....don't worry, I will do it for you...
This may take a minute though
You are super duper awesome!
almost done....I found x for f'(x) ......it's 68.5994, now if you plug that into f''(x)....you will get your min or max
looks like f''(x) is positive....so we have a min at f(x) = 0.69
WOW...awesome...working on it now
That must the minimum cost....I'm guessing...if you plug f(.69) into the function, you will get how many cans is produced....
f(.69) back into the original function that is...
wait...I can't plug those #'s in that fast...lol
264.6 or 265 cans
Wow, what a stumper
Your teacher is just wrong for that one...lol
So the minimum cost is .69 cents to produce 265 cans.
LOL...you are hilarious....I am sure he does not care....this was my 2nd to last problem. I was working on this ALL DAY!
I can imagine
Ur a genius, it only too you ten minutes!
Your teacher must have been laughing to himself when he assigned this problem.
I had a little bit of help...online calcs, graphing calcs and wolfram alpha....Without those, I'm like you...taking all day...
But if you know what to do in the general sense, that helps....the key is knowing that you needed f'(x) and f''(x) to help you find the minimum cost
Awesome.....I did not realize that you could attach files as well
:)
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