Question

how do you integrate ∫7^2x+3 dx ?

Answer 1

is it:
\[\int\limits_{ }^{}7^{(2x+3)}dx\]
?

Answer 2

7^(2x + 3) = e^ln(7^(2x+3))

= e^(2x+3)*ln(7)

so integral is 7^(2x+3)/[ln(7)(2x+3)]

Answer 3

2x+3 =t
2dx = dt
u get
\[\int\limits_{}^{}7^{t}dt/2\]

= 7^(t)ln 7
= 7^(2x+3) (ln7)

Answer 4

wait
its 7^(2x+3)/(2ln7)

Answer 5

sorry

Answer 6

7^(2x + 3) = e^ln(7^(2x+3))

= e^(2x+3)*ln(7)

integral of this is e^(ln(7)*(2x+3))/[2*ln(7)]

which is 7^(2x+3)/ln(49)

Answer 7

ys

Answer 8

did u understand that?

Answer 9

where is the guy who asked this y doesnt he respond