Question

As shown in the figure, OD = 36 cm, OA = 20 cm
and AB = 25 cm. Find the length of chord BC.

Answer 1

Though the figure is not clear, plz try to interpret the given data properly. The options are:
i) 48 cm ii) 56 cm iii) 63 cm iv)68 cm

Answer 2

Is O the centre of the circle or not???

Answer 3

No, ""O" is not the center of the circle.

Answer 4

and the two chords r perpendicular to each other???

Answer 5

Yes.

Answer 6

If two chords intersect inside a circle then the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

This means BO * OC = AO * OD ------- (1)

Here we have the values for OA and OD and if we can find value of either BO or OC, then we can find the value of the remaining length

TrnglAOB is a right angeled trngl, so using Pythagors Theorem

AB^2 = AO^2 + BO^2
25^2 = 20^2 + BO^2
625 = 400 + BO^2
625-400 = BO^2
225 = BO^2
15 cm = BO

so now (1) becomes 15 cm *OC = 20 cm * 36 cm
720 cm^2
OC = ----------- = 48 cm
15 cm

BC = BO + OC = 15cm + 48 cm = 63 cm

Answer 7

Thanks. Really nice explanation. Plz answer my another question. I have posted it.

Answer 8

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Answer 9

I have already clicked "Good Answer" button and given u a medal. Meanwhile, I have posted another question. Please help me out.