Question

UPLOADED need help quick i need to leave

Answer 1

where uploaded?

Answer 2

Okay so:
Suppose you have:
A - original amount
P - amount at time t
k - constant
t - time in years..

Answer 3

Sorry meant t - time in hours.

Answer 4

first put time 't'=0 in the equation to get the total amount of sodium here u will get
5e^0=5
At half time sodium=2.5
Hence
2.5=5e^0.35t
solve using calc u will get half time of sodium in hours

Answer 5

OK. So what you have is the equation that describes the amount of sodium you have in someone's body at any time T. You want to know T1/2, right? So you need to solve for t where t = t1/2.

But what does Half-life mean? When t=t1/2, you have 1/2Ao, where Ao is your original amount. So set t=0, find out what Ao is, and then set 1/2Ao = 5e^(-0.35*t1/2) and solve for t1/2.

Note that t1/2 DOES NOT MEAN t*1/2, but "time at half-life."

Answer 6

actually let me get back to my question 2 ppl are helpin here..

Answer 7

Yes, Sriram has got it. Taking where he left off, 2.5/5=e^-0.35t = 1/2

ln (1/2) = -0.35t

ln(1/2)/-0.35 = t = half life