a man travels a distance of 1.5 meter towards the east, then 2.0 meter towards the south and finally 4.5m towards the east in 4 s. Calculate (2)distance travelled and (b) displacement of the body
displacement = 6.3245 m
distance travelled = 1.5 m + 2.0 m + 4.5 m = 8.0 m
so wats d use of time ? is that useless?
I think it is just given to confuse... It plays no part in distance calculation nor displacement calculation...
ya may be ...
displacement will be equal to the hypotenuse of the Right triangle having base 6m (1.5 + 4.5) altitude 2m Using Pythagoras theorem Hypotnuse^2 = (6m)^2 + (2m)^2 = 36m^2 + 4m^2 = 40m^2 so Hypotenuse = root(40m^2) = 2root(10) m or 6.325 m
we can also use the graph method starting form origin (0,0) and the final position of the man ,i.e, (6,2) From Distance formula D=sqroot* ( (6-0)^2 +(2-0)^2 ) D= 6.3245 m
hey guys if u want to make a ²(square sign) then press alt+253
thanks sukarang !!!
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