Question

What does it mean to refer to a 20 in TVor 25 in-TV set. A 20 in TV set also has a width of 16 inches, what is the height

Answer 1

TV are measured in diagonal

Answer 2

20in is the diagonal. so use the pythagorean theorem (a^2 + b^2 = c^2) to solve.

Answer 3

what is the height

Answer 4

solve using pythagorean formula. width squared + height squared = diagonal squared. (hint: this looks like a 3-4-5 triangle).

Answer 5

I came up with 17 inches

Answer 6

that is not possible.

Answer 7

\[20 = \sqrt{16^2 + height^2}\]\[400 = 16^2 + height^2\]\[400 = 256 + height^2\]\[144 = height^2\]\[height = ???\]

Answer 8

the way I wrote it was 16^2+b^2=18^2, 256+b^2=324, b^2=324-256,256/2=68/2=14/2=17

Answer 9

where'd you get 18? your question said the diagonal was 20.

Answer 10

I think I added 16+2

Answer 11

why?

Answer 12

I am confuse Ithis is my 1 time doing algebra

Answer 13

OK. my first post may have confused you. I meant: \[a^2 + b^2 = c^2\](otherwise known as the pythagorean theorem)

Answer 14

so \[16^2 + b^2 = 20^2\]

Answer 15

but if you recognize that one side is 16, and the diagonal is 20, you might remember that this is a common 3-4-5 right triangle with sides that are 4x longer...

Answer 16

so will it make it 4

Answer 17

so you're telling me \[16^2 + 4^2 = 20^2\]???

Answer 18

I still can't get it sorry

Answer 19

\[a^2+b^2=c^2\]\[b^2=c^2-a^2\]\[b^2=20^2-16^2\]\[b^2=400-256\]\[b^2=144\]\[b=???\]

Answer 20

you understand that \[a^2=a \times a\]right?

Answer 21

yes

Answer 22

is it 72

Answer 23

Then I divide by 2

Answer 24

\[b \times b=144\]

Answer 25

there's no dividing here. it's squares and square roots.

Answer 26

what times itself is 144?

Answer 27

12

Answer 28

:-) !!!!!!!!!!!

Answer 29

so it's a 3-4-5 triangle with sides 4x as large: 12-16-20

Answer 30

Thank you was confuse with dividing instad of square root

Answer 31

no problem.

Answer 32

I have one more question

Answer 33

ok...

Answer 34

Square root ^x15would that be 3

Answer 35

complete the expression

Answer 36

I can't understand what you wrote...

Answer 37

what does "square root ^x15" mean?

Answer 38

its a square root sign 5x on the outside andx^15 inside

Answer 39

\[\sqrt[5]{x^{15}}\]???

Answer 40

yes

Answer 41

\[\sqrt[5]{x^{15}}=(x^{15})^\frac{1}{5}=x^{15\times\frac{1}{5}}=x^3\]

Answer 42

So i just left off the x