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solve for x.x on the outside of sqrt of 2+7=sqrt 3
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As in: \(x\sqrt{2+7}=\sqrt{3}\)?
yes!
\[x \sqrt{2+7}=x \sqrt{9}=\sqrt{3}\implies x=\frac{\sqrt{3}}{\sqrt{9}}=\sqrt{\frac{3}{9}}=\sqrt{\frac{1}{3}}=\frac{1}{\sqrt{3}}\]
that is wrong your possible answers are A.sqrt of 6-7 sqrt of 2 over 2 B:sqrt of 6-7 sqrt of 2 over 4 C.sqrt 3-7 sqrt of 2 over 2
In that case you told me the question wrong. It's A.
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no i didnt i wrote it exactly how it said
I asked you if it was: \(x\sqrt{2+7}=\sqrt{3}\) and you said yes. It's actually: \(x\sqrt{2}+7=\sqrt{3}\).
ohhhhhhhhhhhh
how do you make the sqrt sign?
There's a button for it in equation editor on the 4th tab down but if you want raw latex, it's '\sqrt'.
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