Question

in 1991 the life expectancy of males in a certain country was 64.6 years . in 1995 it was 68.4 years. let E represent the life expectancy in year T represent the number of years since 1991 the liner function E(t) that fits data is e(t)=__ t+__ round to the nearest 10th use the function to predict the life expectancy of males in 2005 E(14)= round to the nearest 10th

Answer 1

I think I did this problem before.......

Answer 2

hmm

Answer 3

x=1
y= 64.6

x=5
y=68.4

Answer 4

e(t)=__ t+__?

Answer 5

E(14)=

Answer 6

y-y1 = M(x-x1)
M = (x-x1)/(y-y1)
M = (5-1)/(68.4-64.6)
M = 4 / 3.8 = 1.0526

Answer 7

y - 64.6 = 1.0526(x-1)
or
E(t) = 1.0526x-1.0526+64.6
E(t) = 1.0526x+63.5474

Answer 8

wait round to the tenth so:
E(t) = 1.1x+63.5

Answer 9

*sorry meant
E(t) = 1.1t+63.5
E(14) = 1.1*14+63.5

Answer 10

E(14) = 78.9

Answer 11

that's the final answer.

Answer 12

thank you sooooooooooo much!!!!