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Consider the function f(x)=xe^−4x, 0≤x≤2. This function has an absolute maximum value equal to ? which is attained at x= ?
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the absolute min is at 0 and 0 respectively.
I got x=1/4 see attached
f'=e^(-4x)-4x*e^(-4x)=0 1-4x=0 x=1/4
if x=1/4 is max, put the value of x in original equation & find f(1/4)
worked, thanks :]
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