determine the area enclosed by y=3x2+10 and y=4x+16
integral of the first curve minus integral of the second curve.
sorry for my bad writing the part where there is the quadratic formula is: \[(2\pm \sqrt{22})/3\]
77.8273
where does the line intersect the parabola? So then you calculate the area under the line - the area under the parabola between those intersecting limits and you get your value. You have to go through the rigor of the analysis so that you understand how it is done though. A strict value won't help, because clearly there is a value to be established, the real question is how do we get there. Set your line and your parabola = and solve your values of x. If it is not factorable then, you either have to complete the square or use the quadratic equation to get your values for x. Both methods are useful tools to have gained by the time you are looking at integral and differential calculus. Often times I keep formulas available in case I forget a detail or two. Do the rigor and more extensive knowledge awaits you.
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