abs of -3x-2<4 two answers
\[\left| -3x-2 \right| < 4\]
im sorry its suppose to be a -3 and not -2
if you were to graph the equation -3x-2 = y and then graph y=4 you could then visualize the area of the graph that must pertain to answer
\left| -3x-3 \right| < 4
yes
\[\left| -3x-3 \right| < 4\]
OK, cool
yep can anyone help me
sorry, was just graphing
so basically you to find the value for x such that when you plug into the equation you will get values between -4 and 4, never equal to 4
let's solve for -3x-3 = 4
ok
because of the negative slope on the X variable, i.e. (-3). X will have a negative value because a negative multiplied by a negative yields a positive
so we want to isolate x, therefore, first add 3 to both sides --> \[-3x - 3 + 3 = 4 + 3\]
--> \[-3x = 7\]
can i stop you for one second ... its suppose to be like a and/or answer
what do you mean?
we are finding the bounds, the values that x can be such that the equation is equals 4 or -4
like x=4/3 or x>9/3 like that
so we if found that x = -7/3, we then find that with -3x-3=-4, that x =-1/3
so between the values \[(-7/3, -1/3)\]
is that suppose to be less then or equal to ...or... greaterthen or equal too
the equation |-3x-3| will be less than 4
ok
just check the concept, if x = -2/3, the equations is (-3)*(-2/3) - 3= 2-3 = -1 ... which is less than 4
so x < -1/3 and x > -7/3
the notation with the parentheses is another way to represent that expression above
\[x = (-7/3, -1/3)\] where the parentheses mean that x cannot equal either of those numbers, but it can equal any number between them
let me know if you need more clarification ;)
it was rong but i posted another problem
Oh, the answers were incorrect?
they need to be in the correct which on is les then the other
sorry, looks like I solved the last part incorrectly, should be 1/3
x > -7/3 and x < 1/3
so -7/3 < x < 1/3
yeah
sorry about that
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