Question

Use the technique developed in this section to solve the minimization problem.
Minimize C = -2x + y
Subject to x + 2y ( or _) 0, y (>or_) 0

Answer 1

graph the 4 inequalities. They you will get a polygon. Find the vertices (corners). Substitute the x and y values of each into the C=
the highest value and lowest value will be the max and min

Answer 2

Not coming up right

Answer 3

well you equation is missing 3x + 2y<=???

Answer 4

12 is the missing number

Answer 5

Here is the graph, only quadrant 1
the vertices are (0,3), (3,1.5), (4,0) and (0,0)

Answer 6

c=-2x+y
0,3 = 3 maximum
3,1.5 = -4.5
4,0 = -8 minimum
0,0 = 0

Answer 7

whenever I try to graph that one, it won't work properly.

Answer 8

what does your graph look like. The equations are in standard form so use intercepts to graph
x+2y=6 (6,0),(0,3)
3x+2y=12 (4,0),(0,6)

Answer 9

Still so very lost...

Answer 10

if the equation is in standard form ax + by = c
the x-intercept is (c/a,0) and the y-intercept is (0,c/b) it makes it easier to graph using those two points

Answer 11

Okay, i'm still trying..

Answer 12

Oh well, going to have to fail this one