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Mathematics 16 Online
OpenStudy (anonymous):

can someone help

OpenStudy (anonymous):

Sure. Hammer away -- we're here to help

OpenStudy (anonymous):

with wat?

OpenStudy (anonymous):

OpenStudy (anonymous):

i cant see sorry

OpenStudy (anonymous):

Well, since you're being asked this question I'm sure you've already seen the formula\[y2-y1/x2-x1\] What this means is if you insert any two coordinates from a straight line (or tangent line) (x1, y1) and (x2, y2), you can find the rate of change of the line, or in other words the slope.

OpenStudy (anonymous):

Using what you have, with (4,5) = (x2, y2) and (-2, 2) = (x1, y1), \[5-2/4-(-2) = 3/4+2=3/6=1/2\] There's the slope.

OpenStudy (anonymous):

Woops! The eqn should be 5−2/[4−(−2)]=3/(4+2)=3/6=1/2

OpenStudy (anonymous):

thanks soo much i get it now

OpenStudy (anonymous):

Great :D

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