simplify (p^-8)-3 I got an answer p^24 is this correct
right one!
What class are you taking? I do not think this answer is right. I am in Intermediate Algebra, we just did this last week. I do not think you multiply the exponents. I am looking in my book, give me a second to atleast double check to make sure.
a^-n=1/a^n
is it \[(p ^{-8})^{-3}\]
That is the rule for a negative exponent.
Nickie_S I am in Algebra1B
if t is as i wrote then we use the law \[(a ^{m})^{n} = a ^{m*n}\] and get \[p ^{(-8)*(-3)} = p ^{24}\]
thnks Harkirat that is what I go to
so the question is as I wrote???
Harkirat that is how I set it up to solve also
Nickie_S do u hv a different opinion/answer??
ok jazil then while posting the question type it as follows: simplify (p^-8)^-3 you missed the second carat sign (^)
I am looking it up, I thought you plus or minus, but the thing is I haven't came across a - and - exponent in my book. I am no expert so I may be wrong.
thanks Harkirat I sure did miss the second carat sign but u were smart enough to know exactly what I meant
@ Nickie_s the laws remain same whether indices are positive or negative......
41. (t^-3)^-6 t^18 I finally found it, I think yeah you multiply the exponents. its right. (See it was a learning question, lol) Sorry.
see we can even handle it by the law a^-m = 1/a^m ( 1 )^-3 (p^-8)^-3 =(---- ) ( p^8 ) now we will have to use the law when base is fraction \[(p/q)^{-m} = (q/p)^{m}\]
so it becomes ( p^8 )^3 p^8*3 p^24 (p^-8)^-3 =(---- ) = ------- = ------ = p^24 !!!!!!! ( 1 ) 1^3 1
So Nickie_S you can see that is a longer and more complicated way of doing it so first method is nice, short, clean... ☺☻☺
lol, I always go for the long way. I just thought there was something else to it. So its not 1/(p^8)^3 which then turns into p^24. See I thought it was (p^-8)^-3 =p^(-8+-3) =p^-11
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