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Mathematics 19 Online
OpenStudy (anonymous):

Find the distance on the coordinate system from the point (-3, 4) to the point (8, -7).

OpenStudy (aroub):

ok, distance formula: \[\sqrt{(x1-y1)+(x2-y2)}\]

OpenStudy (anonymous):

you forgot squared symbols, lol

OpenStudy (anonymous):

and that's wrong

OpenStudy (aroub):

lol, sorry

OpenStudy (anonymous):

\[d=\sqrt{(x-x1)^{2}+(y-y1)^{2}}=\]

OpenStudy (aroub):

ok its \[\sqrt{(x1-y1)^{2}+(x2-y2)^{2}}\]

OpenStudy (anonymous):

11sqrt 2

OpenStudy (anonymous):

\[d=\sqrt{11^{2}+11^{2}}=...\]

OpenStudy (anonymous):

aroub, that still isnt' right...inik got it right

OpenStudy (aroub):

why hero ??

OpenStudy (dumbcow):

to try to understand it, plot the points and think of the distance as the hypotenuse of right triangle, with the legs being the x,y distances from the points

OpenStudy (anonymous):

11 square root of 2 is the answer

OpenStudy (dumbcow):

distance formula really is just the pythagorean thoerem

OpenStudy (anonymous):

heromiles is right. you can re-write: \[d=\sqrt{11^{2}+11^{2}}=\sqrt{2*11^{2}}=11\sqrt{2}\]

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