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Find the distance on the coordinate system from the point (-3, 4) to the point (8, -7).
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ok, distance formula: \[\sqrt{(x1-y1)+(x2-y2)}\]
you forgot squared symbols, lol
and that's wrong
lol, sorry
\[d=\sqrt{(x-x1)^{2}+(y-y1)^{2}}=\]
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ok its \[\sqrt{(x1-y1)^{2}+(x2-y2)^{2}}\]
11sqrt 2
\[d=\sqrt{11^{2}+11^{2}}=...\]
aroub, that still isnt' right...inik got it right
why hero ??
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to try to understand it, plot the points and think of the distance as the hypotenuse of right triangle, with the legs being the x,y distances from the points
11 square root of 2 is the answer
distance formula really is just the pythagorean thoerem
heromiles is right. you can re-write: \[d=\sqrt{11^{2}+11^{2}}=\sqrt{2*11^{2}}=11\sqrt{2}\]
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