Question

Solve for y
y+4/2y + y-2/ 3 = 3y^2+10/ 6y

Answer 1

How far did you get before getting stuck? Also, do you know how to solve this graphically?

Answer 2

Using parenetheses would be helpful

Answer 3

(y+2)/(2y) + (y-2)/(3) = (3y^2+10)/(6y)

Answer 4

thank you

Answer 5

\[\frac{y+2}{2y}+\frac{y-2}{3}=\frac{3y^2+10}{6y}\]
\[6y*\frac{y+2}{2y}+6y*\frac{y-2}{3}=6y*\frac{3y^2+10}{6y}\]

Answer 6

6y(y+2)(y-1)

Answer 7

If you go to http://www.wolframalpha.com and type solve (y+2)/(2y) + (y-2)/(3) = (3y^2+10)/(6y) and then click "Show steps" you can get a detailed breakdown of the solution.

It gives a complex answer, though, so I'm wondering if you copied the problem correctly?

Answer 8

lol

Answer 9

3(y+2)+2y(y-2)=3y^2+10

Answer 10

3y+6+2y^2-4y=3y^2+10
3y^2+10-3y-6-2y^2+4y=0
y^2+y+4=0
you can solve the rest of this using the quad formula

Answer 11

He changed the problem

Answer 12

The first term was y+4 in teh denom, then it became y+2

Answer 13

:/

Answer 14

good eye
so we have two problems here and i did the second one not the first one

Answer 15

I did the first one, lol

Answer 16

It's the original one.

Answer 17

That website helped though.

Answer 18

If it's the original one, then mine is right.

Answer 19

mine is right lol