Question

e^(1+ln(7))

Answer 1

\[e^{1+\ln(7)}=e^1\times e^{\ln(7)}=e\times 7=7e\]\]

Answer 2

last equality because
\[e^{\ln(x)}=x\]

Answer 3

Sweetness thanks!

Answer 4

first equality because
\[b^nb^m=b^{n+m}\] and you are certainly welcome!