Question

need a solutions
√(y+10)=y-2

Answer 1

(y+10)=(y-2)^2
y+10=y^2-4y+4
y^2-5y-6=0
can you solve this quadratic equation?

Answer 2

nop

Answer 3

use quadratic formula:
\[y=(5\pm \sqrt{5^{2}-4*(-6)})/2*1=(5\pm7)/2\]

Answer 4

y1=6 and y2=-1
this are the roots of quadratic equation/ solution(s)
now you need to check if both solutions are good - put the values in original equation:
if y=6, then:
\[\sqrt{6+10}=6-2\]
4=4 is a true statement the root is good.

if y=-1, then:
\[\sqrt{-1+10}=-1-2\]
3=-3 is not a true statement, so y=-1 is not a solution.

Answer: y=6 (only one solution)

Answer 5

thanks alot

Answer 6

sure:)