Question

sinx/1+cosx =1-cosx/sinx
identities

Answer 1

i think she means
\[\frac{sinx}{1+cosx}=\frac{1-cosx}{sinx}\] is that right?

Answer 2

yes

Answer 3

cross multiply. add cos^2x on both sides

Answer 4

Cross multiply :)

Answer 5

i dont think you can do when you are trying to show something is something

Answer 6

\[\frac{sinx}{1+cosx}*\frac{1-cosx}{1-cosx}=\frac{sinx*(1-cosx)}{1-\cos^2x}=\frac{sinx*(1-cosx)}{\sin^2x}\]

Answer 7

=\[\frac{1-cosx}{sinx}\]

Answer 8

and what would be the domain restriction on that?

Answer 9

you don't want the bottom to be zero
find when sinx=0 and whenever that happens thats what you want to exclude from your domain