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integral sin(x^2)=?
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it's a Freshnel integral.
why?
Because there is not integral for that in elementary functions.
No integral*
I thing this the answer (-cos(x^2)/2x)+c is it right?
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You can expand sin(x^2) into a series and integrate it approximately
ok thank you
The expansion for sine as a series is: \[\sum_{n=0}^{\infty}\frac{(-1)^n x^{2n+1}}{(2n+1)!}= sin(x)\] If you replace x with x^2. You can then integrate it and approximate it. \[\int\limits \sum_{n=0}^{\infty}\frac{(-1)^n x^{4n+2}}{(2n+1)!}dx\]
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