What is the limit as x approaches +infinity of x^100/e^x? Use L'Hopital?
derive the top; derive the bottom; and apply the value of x=inf
I did that, but in doing the derivatives, I got 100x^99/e^x, which when evaluated at infinity is still infinity over infinity, which gets me no where....if I'm doing that right?
http://www.wolframalpha.com/input/?i=limit+%7Bx+to+infinity%7D++x%5E100%2Fe%5Ex this is to verify the answer
0
with your eyeballs
1/e^x = e^(-x) right?
point is that you can use l'hopitals rule if you like. you will use it 100 times. the degree of the numerator will decrease by 1 each time and the denominator will still be \[e^x\]
the real point is that in the long run \[e^x\] grows faster than any polynomial, no matter what the degree. that is why i said you do it with your eyeballs
ah..I got it now. Thanks guys.
so no, you do not need l'hopital. just know that exponentials grow faster than polynomials
yw
it helps to know the limit of e^(-x) as x gets larger :)
oh look i didn't even notice until now! i am a \[\color{green}{\text{guru}}\]
How about x! ?
lol .... guess you made it to 70; im wondering what the 80s are gonna be ::hoping megamind:: lol
that is a good question. but of course x! is not a polynomial!
the 80's will feature new wave music and good drugs
the editor will need to be upgraded for that...
ho ho. btw i n! grows faster than exp(n) yes?
Yes, I reckon..
While I am in here, is the javascript on the site causing headaches for anyone? I'm having to use Safari, the others keep crashing.
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