Question

Solving equations with Radicals:-
sqr x^2+15x-6=x

Answer 1

you need to use (...)s to indicate what is spose to be under the radical sign.

sqrt(x^2 +15x -6) = x would be appropriate, otherwise we got no idea what you need from it

Answer 2

I'm assuming you mean:

\[\sqrt{x^2 + 15x - 6}=x\]

In that case:

square both sides:
\[x^2+15x-6 = x^2\]
\[15x-6=0\]
\[15x=6\]
\[x=6/15\]

Answer 3

usually the idea is to get rid of the radical by squaring both sides

Answer 4

oh yes u r right

Answer 5

with radicals, always check for extraneous solutions :)
plug it back in and make sure it works

Answer 6

sqrt(x^2) +15x -6 = x would be:

x +15x -6 -x = 0

15x -6 = 0

15x = 6

x = 6/15 = 2/5