Solving equations with Radicals:-
sqr x^2+15x-6=x

Question

amistre64 · Answer

you need to use (...)s to indicate what is spose to be under the radical sign.

sqrt(x^2 +15x -6) = x  would be appropriate, otherwise we got no idea what you need from it

anonymous · Answer

I'm assuming you mean:

$$\sqrt{x^2 + 15x - 6}=x$$

In that case:

square both sides:
$$x^2+15x-6 = x^2$$
$$15x-6=0$$
$$15x=6$$
$$x=6/15$$

dumbcow · Answer

usually the idea is to get rid of the radical by squaring both sides

anonymous · Answer

oh yes u r right

dumbcow · Answer

with radicals, always check for extraneous solutions :)
plug it back in and make sure it works

amistre64 · Answer

sqrt(x^2) +15x -6 = x would be:

x +15x -6 -x = 0

15x -6 = 0

15x = 6

x = 6/15 = 2/5