In 1992, the life expectancy of males in a certain country was 65.4 years in 1999 it was 69.2 years. Let E represent the life expectancy in year t and let t represent the number of years since 1992. The linear function E(t) that fits the data is E(t)=____t+_____ (round to the nearest tenth) Use the function to predict the life expectancy of males in 2003 (round to the nearest tenth.)
The first thing you'll want to do is use the information you have about 1992 to give you part of the equation. You know that 0 years after 1992, the life expectancy is 65.4 years. SO when t=0, it doesn't really matter what the first blank is, because you're multiplying it by 0. so that tells you that the second blank (the intercept) is 65.4. To find the first blank (the slope), you know that in 1999, the life expectancy is 69.2 years. So write the formula again, with the E(7) = m*7 + 65.4, and solve for m. Then, just figure out what t equals in 2003, and solve for E(t).
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