Question

y=tanx/x2 what is d/dy

Answer 1

are you sure its d/dy and not d/dx?

Answer 2

I'm assuming this is an implicit problem:
\[\frac{d}{dy}(y=\frac{\tan(x)}{x^2})\]
This gives:
\[\frac{\sec(x)\tan(x)x^2-\tan(x)(2x)}{(x^2)^2}*\frac{dx}{dy}\]
If it is d/dx. Then it is:
\[\frac{dy}{dx}=\frac{\sec(x)\tan(x)x^2-\tan(x)(2x)}{(x^2)^2}\]

Answer 3

here you can use the quotient rule or the product rule (tanx * (2x)^-1)