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Mathematics 7 Online
OpenStudy (anonymous):

If f is a continuous function defined for all real numbers x and the maximum value of f(x) is 5 and the minimum is -7, then which must be true? I The maximum value of f(IxI) is 5 II The maximum value of If(x)I is 7 III The minimum value of f(IxI) is 0 those are absolute value marks

OpenStudy (anonymous):

I

OpenStudy (anonymous):

There's probably an actual rule to be applied here, but... We have 3 important points here: \[f(a) = 5, f(b) = 0, f(c) = -7\] Because we don't have an actual graph, we cannot say anything about excluding the negative side of the graph which is what happens when we find the absolute value of x before putting it into f(x). We can, however, say that if the maximum before was 5 and the minimum was -7, after finding the absolute value there is now a point somewhere that has a value of 7. As this is higher than the previous maximum, II can be said to be true. Therefore, The answer is II only.

OpenStudy (anonymous):

number II is correct. as I is maximum value of f(x>0) = 5, we dont know whether the maximum lies compared to x = 0 and II is maximum values of absolute value of f(x) = 7, as 7 is the largest value when we dont care about the sign this is true, and III is the same case a I

OpenStudy (anonymous):

Reread II: It says "The maximum value of If(x)I is 7," not "The maximum value of f(|x|) is 7

OpenStudy (blacksteel):

Ah, my apologies - you are correct.

OpenStudy (anonymous):

I'm pretty sure II is right, I dont understand how I is

OpenStudy (blacksteel):

It is II, I misread the problem.

OpenStudy (anonymous):

so I is not true at all? because there is an option that includes both one and two

OpenStudy (anonymous):

I isnt right, we dont know if the f(x) has a maximum of 5 when x > 0

OpenStudy (blacksteel):

1 is not necessarily true; if the maximum value of f(x) occurs when x < 0, then it won't be reachable in f(|x|) and thus the maximum value of f(|x|) will be less than 5.

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