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Mathematics 17 Online
OpenStudy (paige):

Silly me, I forgot how to differentiate -.-'' Can you differentiate x(4x+12)^1/2 to give it in the form of k(x+2)/(4x+12)^1/2. Can you give it stepwise please? :)

OpenStudy (anonymous):

what is being raised to the power of 1/2?

OpenStudy (amistre64):

The product rule is : [lr]' = l'r + lr' The power rule (exponents rule) is: [x^n]' = n.x^(n-1)

OpenStudy (paige):

@satellite73 The (4x+12)

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