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Mathematics 14 Online
OpenStudy (anonymous):

Use the theorems to find x in the following circles. x = please help

OpenStudy (anonymous):

OpenStudy (anonymous):

click good answer if I desever

OpenStudy (anonymous):

its not right

OpenStudy (anonymous):

what is the key?

OpenStudy (anonymous):

x=3+9 =12

OpenStudy (anonymous):

If a tangent segment and a secant segment intersect outside a circle, then the square of the measure of the tangent segment equals the product of the measures of the secant segment and its external portion. => 6^2=3*x 36=3x 36/3 = x 12 = x

OpenStudy (anonymous):

I positive I correct

OpenStudy (anonymous):

see my solution, that is the correct application of the theorem i mentioned...

OpenStudy (anonymous):

sorry give y frist and y+x=9+3=12

OpenStudy (anonymous):

Use the theorems to find x in the following circles. x =

OpenStudy (anonymous):

i forgot give y indtate x solve y =9 y+3=x x=9+3 x=12 my answer it correct

OpenStudy (anonymous):

pls see the wording of the theorem " product of the measures of the secant segment and its external portion." here secant segment is = x external portion = 3 so their product is 3*x

OpenStudy (anonymous):

OpenStudy (anonymous):

4*3 = 2*x 12/2 = x 6 = x

OpenStudy (anonymous):

2x=4*3

OpenStudy (anonymous):

x=6

OpenStudy (anonymous):

6^2=3(3+y) 36=3(3+y) 36=9+3y 3y= 36-9 y= 27/3 y =9 x=9+3 x=12

OpenStudy (anonymous):

I missup y=x

OpenStudy (anonymous):

no problem ☺ but if full secant and its outer segment are given, then my method is direct and easier...

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