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∫e^(-x^2)
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i believe this is one of those that doesnt have a nice ending ...
yes it does you need to be very creative
limits of integration are from 0 to infinity
wolfram gets rather creative with it :)
look up guassian integrals
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Couldnt you use the infinite series form of e^(-x^2) and integrate each part? (Just taking some jabs at this, haven't thought about it too long, dont kill me <.<) lol
use substitution law let u=-x^2
gaussian is not my speed yet :)
\[∫∫e^{-(x ^{2}+y ^{2})}\]=∫∫[0,infinity][0,pi/2],e^-r^2rdrd(theta) then do then integral switch order of integration and you will get \[\sqrt{\pi}/2\]
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