Question

Let P(x,y) be a point (other than (-1, -1) on the graph of f(x) = x^3. Express the slope of the line passing through the points P and (-1, -1) as a function of x.

Answer 1

Oh that's easy, right?

Answer 2

Slope is change in y over change in x. y = x^3.
(x^3+1)/(x+1)

Answer 3

I'm tutoring someone right now, and I can't believe I can't do this. I'm fried from my final today.

Answer 4

It happens....

Answer 5

You need to find the derivative the long way

\[(f(x) - f(x + h) \over h\]\[-1^3 - (-1+Px)^3 \over Px\] do lots of working... factor out the Px from the top and cancel out with the bottom and get\[-1 + 3px - px^2\] which I think is right. But you get the method hopefully.. no idea why I called it Px

Answer 6

I kind of lost track of what I was doing halfway through so I hope that's right :/

Answer 7

huh?

Answer 8

derivative = slope

Answer 9

she just wants the equation for the slope of a line through the points (-1,-1) and (x,x^3).

Answer 10

m = (y2 - y1) / (x2 - x1)

Answer 11

Good job hick ninja

Answer 12

nice one hick ninja