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An original rectangle has a length of 10 and a width of 28. What happens to the area if the new width is one quarter the original width? Verify your answer.
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The new width is going to be \[\frac{1}{4}(28) = 7\] So the area is now A = (10)(7) = 70, which happens to be 1/4 the old area
\[10\times 28\] vs \[10\times 7\]
first one is 280, second one is 70, one fourth of the first one what joemath said
Specifically, in your case it sounds like your teacher wants you to intuit the fact that the area is reduced by a factor of four, then verify it with the above multiplication.
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