Question

\[\sum_{0}^{\infty} 1\div \left( \sqrt{2} \right)^{n}\]

Answer 1

did u check if it converges?

Answer 2

no how do i go about that

Answer 3

It's a geometric series, since sqrt(2) > 1, it converges, to a formula you really should look up and memorize.

Answer 4

the one where it says -1<r<1?

Answer 5

and since it is convergent how do i find its sum?

Answer 6

No, I'll give it:
\[\sum_{n=0}^{\ \infty}(\frac{1}{k})^n=\frac{1}{1-\frac{1}{k}}\]

Answer 7

thats it?

Answer 8

Yes.

Answer 9

i thought it was more complicated

Answer 10

Nope. Pretty straight-forward.

Answer 11

wow thank you

Answer 12

where is the good answer button haha?

Answer 13

Right side of the tan bar with your name in it.

Answer 14

thanks

Answer 15

Any time.