Help? An Eskimo is standing on a floating iceberg headed due east at 8 mph. If the stream is flowing due north at 5 mph, find the velocity (magnitude) of the iceberg. Show all work
The speeds represent the two legs of a triangle. Using the Pythagorean Theorem we get 64+25= x^2...solving for x yields an answer of approximately 10.44 mph northeast.
It seems to have cut off the full question...
An Eskimo is standing on a floating iceberg headed due east at 8 mph. If the stream is flowing due north at 5 mph, find the resultant direction and velocity (magnitude) of the iceberg. Show all work.
Resultant Direction = √ ( 8^2 + 5^2) Resultant Direction = √(64+25) Resultant Direction = √89 Resultant Direction = 9.43 mph is what i have so far
help?
okay i will
Well, this is difficult to explain without drawing, but suppose You know how to draw 2D vectors. One arrow pointing right of length 8 (representing movement due east) and another arrow pointing upwards of length 5 (representing movement due north). Both arrows start from the same initial (reference) point, representing the iceberg. Their resultant is a diagonal arrow pointing northeast. Its length is sqrt(5^2+8^2) = 9.434, so this is the resultant speed (velocity magnitude) in mph. As to the direction, the angle between the north and the resultant determines its direction: 5/8 = tan(90deg-angle) This should be obvious from the drawing. Now: arctan(5/8) = 90deg-angle from which the angle can be calculated to be 58 degrees. Hence, the answer, if I didn't make any calc mistakes, should be exactly 58 degrees northeast. The role of the eskimo there is not very clear (?)
haha okay thank you so much you really helped me out!!!
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